5w^2-490=0

Solution for 5w^2-490=0 equation:

5w^2-490=0

a = 5; b = 0; c = -490;
Δ = b2-4ac
Δ = 02-4·5·(-490)
Δ = 9800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9800}=\sqrt{4900*2}=\sqrt{4900}*\sqrt{2}=70\sqrt{2}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70\sqrt{2}}{2*5}=\frac{0-70\sqrt{2}}{10}
=-\frac{70\sqrt{2}}{10}
=-7\sqrt{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70\sqrt{2}}{2*5}=\frac{0+70\sqrt{2}}{10}
=\frac{70\sqrt{2}}{10}
=7\sqrt{2}
$